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Let O be the in-centre of a triangle ABC and D be a point on the side BC of ΔABC, such that OD ⊥ BC. If ∠BOD = 15°, then ∠ABC = ?
Answer & Solution
Correct Answer:
Option
C
According to question,
Given : ∠BOD = 15°
∴ ∠BDO + ∠DOB + ∠DBO = 180°
∠DBO = 75°
∠ABC = 2 × ∠DBO
∠ABC = 2 × 75°
∠ABC = 150°
Given : ∠BOD = 15°
∴ ∠BDO + ∠DOB + ∠DBO = 180°
∠DBO = 75°
∠ABC = 2 × ∠DBO
∠ABC = 2 × 75°
∠ABC = 150°
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