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The ratio of milk to water in a 100 litres mixture is 2 : 3. 10 litres of this mixture is withdrawn and replaced with milk. This process is repeated 2 more times. What is the percentage of milk in final mixture?
Answer & Solution
Correct Answer:
Option
D
\[\begin{array}{*{20}{c}}
{{\text{Milk}}}&{}&{{\text{Water}}}&{} \\
\begin{gathered}
2 \hfill \\
\downarrow \hfill \\
\end{gathered} &\begin{gathered}
: \hfill \\
\hfill \\
\end{gathered} &\begin{gathered}
3 \hfill \\
\downarrow \hfill \\
\end{gathered} &\begin{gathered}
= 5 \to 100 \hfill \\
\,\,\,1 \to 20 \hfill \\
\end{gathered} \\
{40}&{}&{60}&{}
\end{array}\]
$$\eqalign{ & = 60{\left( {1 - \frac{{10}}{{100}}} \right)^3}\% \cr & = 60{\left( {\frac{9}{{10}}} \right)^3}\% \cr & = 60 \times \frac{{729}}{{1000}}\% \cr & = 43.74\% \cr & \therefore {\text{Final milk }}\% = \left( {100 - 43.74} \right)\% \cr & = 56.26\% \cr} $$
$$\eqalign{ & = 60{\left( {1 - \frac{{10}}{{100}}} \right)^3}\% \cr & = 60{\left( {\frac{9}{{10}}} \right)^3}\% \cr & = 60 \times \frac{{729}}{{1000}}\% \cr & = 43.74\% \cr & \therefore {\text{Final milk }}\% = \left( {100 - 43.74} \right)\% \cr & = 56.26\% \cr} $$
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