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Two vessels A and B contains acid and water in the ratio 4 : 3 and 5 : 3 respectively. Then the ratio in which these mixtures to be mixed to obtain a new mixture in vessel C containing acid and water in the ratio 3 : 2 is -
Answer & Solution
Correct Answer:
Option
B
According to the question,
$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{Acid}}\,\,\,\,\,\,\,{\text{Water}} \cr & {\text{Vessel A}}\,\,\,\,\,{\text{4}}\,\,\,\,:\,\,\,\,{\text{3}} \cr & {\text{Vessel B}}\,\,\,\,\,\,{\text{5}}\,\,\,\,{\text{:}}\,\,\,\,\,{\text{3}} \cr} $$
Now using alligation,
$$\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{Acid}}\,\,\,\,\,\,\,{\text{Water}} \cr & {\text{Vessel A}}\,\,\,\,\,{\text{4}}\,\,\,\,:\,\,\,\,{\text{3}} \cr & {\text{Vessel B}}\,\,\,\,\,\,{\text{5}}\,\,\,\,{\text{:}}\,\,\,\,\,{\text{3}} \cr} $$
Now using alligation,
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