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A shopkeeper cheats to the extent of 10% while buying as well as selling, by using false weights. His total gain is -
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{Rule}}:{\text{Gain}}\% \cr
& = \frac{{{{\left( {100 + {\text{common gain}}\% } \right)}^2}}}{{100}} - 100 \cr
& \therefore {\text{Gain }}\% \cr
& = \left[ {\frac{{{{\left( {100 + 10} \right)}^2}}}{{100}} - 100} \right]\% \cr
& = \left( {\frac{{12100 - 10000}}{{100}}} \right)\% \cr
& = 21\% \cr} $$
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