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81
The unit digit in the product 771 × 663 × 365 = ?
Discuss
Answer & Solution
Answer: Option D
Solution:
    771   ×   663   ×   365
    ↓   ↓   ↓
Unit Place   73   63   31
    ↓   ↓   ↓
Unit Digit ⇒ 3   ×   6   ×   3 = 54
  ⇒ 4 is answer
82
If sum of the two number is 80 and ratio is 3 : 5, then find numbers :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let number are a, b = 3x, 5x
So, 3x + 5x = 8x = 80
x = 10
So, number is :
3 × 10 = 30
5 × 10 = 50
83
$$\frac{2}{3}$$ of three-fourth of a number is :
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & = \frac{2}{3} \times \frac{3}{4} \times n\,\,\,\left( {{\text{n}}\,{\text{is}}\,{\text{a}}\,{\text{number}}} \right) \cr & = \frac{1}{2}n \cr} $$
84
The greatest four digit number which is exactly divisible by each one of the numbers 12, 18, 21 and 28 :
Discuss
Answer & Solution
Answer: Option A
Solution:
L.C.M of 12, 18, 21, 28 = 252
9999 is divided by 252
Then remainder is 171
= 9999 - 171
The number will be = 9828
85
A number exceeds its two fifth by 75. The number is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the number = x
⇒ According to the question,
$$\eqalign{ & \Rightarrow x - \frac{2}{5}x = 75 \cr & \Rightarrow \frac{{5x - 2x}}{5} = 75 \cr & \Rightarrow 3x = 75 \times 5 \cr & \Rightarrow x = 125 \cr} $$
86
The smallest number, which should be added to 756896, so as to obtain a multiple of 11, is :
Discuss
Answer & Solution
Answer: Option C
Solution:
For divisibility of 11
= 756896
= (9 + 6 + 7) - (6 + 8 + 5)
= 3
So, 3 should be added to number to make it divisible by 11
87
If sum of two numbers be a and their product be b, then the sum of their reciprocals is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the two number are P and Q
P + Q = a
PQ = b
⇒ $$\frac{{1}}{{P}}$$ + $$\frac{{1}}{{Q}}$$
⇒ $$\frac{{Q + P}}{{PQ}}$$
⇒ $$\frac{{a}}{{b}}$$
88
If the numbers $$ \root 3 \of {9} , \root 4 \of 20 , \root 6 \of {25} $$   are arranged in ascending order, then the right arrangement is -
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\root 3 \of 9 ,\,\,\root 4 \of {20} ,\,\,\root 6 \of {25} $$
Taking L.C.M of 3, 4 and 6
$$\eqalign{ & = \root {12} \of {{9^4}} ,\,\,\root {12} \of {{{20}^3}} ,\,\,\root {12} \of {{{25}^2}} \cr & = \root {12} \of {6561} ,\,\,\root {12} \of {8000} ,\,\,\root {12} \of {625} \cr} $$
So, ascending order
$$ = \root 6 \of {25} , < \root 3 \of 9 , < \root 4 \of {20} $$
89
Which of the following fraction is the smallest ?
$$\frac{8}{{15}},$$ $$\frac{{14}}{{33}},$$ $$\frac{7}{{13}},$$ $$\frac{{11}}{{13}}$$
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\frac{8}{{15}},\frac{{14}}{{33}},\frac{7}{{13}},\frac{{11}}{{13}}$$

(264) , (210)  
↑   ↑  
$$\frac{8}{{15}}$$   ⤩   $$\frac{14}{{33}}$$  = $$\frac{8}{{15}}$$ > $$\frac{14}{{33}}$$
(182) , (231)  
↑   ↑  
$$\frac{14}{{33}}$$   ⤩   $$\frac{7}{{13}}$$  = $$\frac{14}{{33}}$$ < $$\frac{7}{{13}}$$ < $$\frac{11}{{13}}$$

$${\text{So}}\frac{{14}}{{33}}\,{\text{is}}\,{\text{smallest}}$$
90
When 'n' is divisible by 5 the remainder is 2. What is the remainder when n2 is divided by 5 ?
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & \frac{{\text{n}}}{5} \Rightarrow {\text{remainder}}\,\,2 \cr & {\text{if we put n = 7}} \cr} $$
Then it satisfies above situation
$$\eqalign{ & {\text{so n = 7}} \cr & \frac{{{{\text{n}}^2}}}{5} = \frac{{{7^2}}}{5} = \frac{{49}}{5} \cr & \Rightarrow {\text{remainder = 4}} \cr} $$