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41
A's salary is 50% more than that of B. Then B's salary is less than that of A by :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let salary of B = 100
∴ Salary of A = 100 + 50% of 100 = 150
B salary is lesser then A = 150 - 100 = 50
Required %
= $$\frac{50}{150}$$ × 100 = $$33\frac{1}{3}$$%
42
If 60% of A = 30% of B, B = 40% of C and C = x% of A, then value of x is :
Discuss
Answer & Solution
Answer: Option D
Solution:
According to the question,
A : B : C
1 : 2 : 5 ( 60A = 30B)
$$\frac{A}{B}$$ = $$\frac{1}{2}$$
C = 5
A = 1
Required answer = $$\frac{5}{1}$$ × 100 = 500%
43
In an examination 70% of the candidate passed in English, 80% passed in Mathematics, 10% failed in both subjects. If 144 candidates passed in both, the total number of candidates was :
Discuss
Answer & Solution
Answer: Option C
Solution:
Failed candidates in English = (100 - 70) = 30%
Failed candidates in Mathematics = (100 - 80) = 20%
Candidates who fail in both subject = 10% Candidates who only fail in English = 30 - 10 = 20%
Candidates who only fail in Mathematics = 20 - 10 = 10%
Percentage of passed students in both subject
= 100 - (Candidates who only fail in English + Candidates who only fail in Mathematics + Candidates who fail in both subject)
= 100 - (20 + 10 + 10)
= 60%
According to the question,
60% of students = 144
Total students :
= $$\frac{144}{60}$$ × 100
= 240
44
Raman's salary is increased by 5% this year. If his present salary is Rs. 1806, the last year's salary was :
Discuss
Answer & Solution
Answer: Option A
Solution:
Required last year salary
= $$\frac{1806}{100 + 5}$$   × 100
= Rs. 1720
45
If 80% of A = 50% of B and B = x% of A, then the value of x is :
Discuss
Answer & Solution
Answer: Option C
Solution:
80% of A = 50% of B
⇒ $$\frac{80}{100}$$A = $$\frac{50}{100}\,$$B
⇒ 8A = 5B
⇒ A = $$\frac{5}{8}$$B
Put value of A in given equation,
B = x% of A
⇒ B = $$\frac{x}{100}$$ × $$\frac{5}{8}\,$$B
⇒ x = $$\frac{100 × 8}{5}$$
⇒ x = 160
46
The percentage of metals in a mine of lead ore is 60%. Now the percentage of silver is $$\frac{3}{4}$$% of metals and the rest is lead. If the mass of ore extracted from this mine is 8000 kg, the mass (in kg.) of lead is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Mass of lead ore = 8000 kg
⇒ Mass of metal in lead ore
= 60% of 8000
= 4800 kg
⇒ Mass of silver in metal
= $$\frac{3}{4}$$% of 4800
= 36 kg
⇒ Mass of lead in ore
= 4800 - 36
= 4764 kg
47
If 120 is 20% of a number, then 120% of that number will be :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the number = x
According to the question,
x × $$\frac{20}{100}$$ = 120
x = 600
Required answer
= 600 × $$\frac{120}{100}$$ = 720
Alternate
20% represents → 120
                    1% → $$\frac{120}{20}$$
So, 120% = $$\frac{120}{20}$$ × 120
                 = 720
48
498 is 17% less than a number then the number is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the number = x
According to the question,
⇒ x - $$\frac{17x}{100}$$ = 498
⇒ 100x - 17x = 49800
⇒ 83x = 49800
⇒ x = $$\frac{49800}{83}$$ = 600
49
If radius of a circle is increased by 5%, then the increase in it's area is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Quicker approach
$$ \uparrow $$   in A = a + b + $$\frac{ab}{100}$$
Here a = b = 5%
$$ \uparrow $$   in A :
$$\eqalign{ & = \left( {5 + 5 + \frac{{5 \times 5}}{{100}}} \right)\% \cr & = 10.25\% \cr} $$
50
If 60% of A's income is equal to 75% of B's income, then B's income is equal to x% of A's income. The value of x is :
Discuss
Answer & Solution
Answer: Option C
Solution:
According to the question,
⇒ 60 × $$\frac{A}{100}$$ = 75 × $$\frac{B}{100}$$
⇒ 4A = 5B
⇒ B = $$\frac{4}{5}$$A
⇒ A × $$\frac{x}{100}$$ = B (given)
⇒ A × $$\frac{x}{100}$$ = $$\frac{4}{5}$$A
⇒ x = 80