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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-5 section-5

Each section contains 100 MCQs on Percentage .
41
If the price of a book is first decreased by 25% and then increased by 20%, then the net charges in the price will be :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the original price be Rs. 100
New final price :
= 120% of (75% of Rs. 100)
= Rs. $$\left( {\frac{{120}}{{100}} \times \frac{{75}}{{100}} \times 100} \right)$$
= Rs. 90
∴ Decrease = 10%
42
The current birth rate per thousand is 32, whereas the corresponding death rate is 11 per thousand. The net growth rate in terms of population increase in percent is given by :
Discuss
Answer & Solution
Answer: Option C
Solution:
Net growth on 1000
$$= (32 - 11)$$
$$= 21$$
Net growth on 100
$$\eqalign{ & = \left( {\frac{{21}}{{1000}} \times 100} \right)\% \cr & = 2.1\% \cr} $$
43
A reduction of 21% in the price of wheat enables a person to buy 10.5 kg more for Rs. 100. What is the reduced price per kg ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the original price = Rs. $$x$$ per kg
Reduced price = Rs. $$\left( {\frac{{79x}}{{100}}} \right)$$ per kg
$$\eqalign{ & \therefore \frac{{100}}{{79x}} - \frac{{100}}{x} = 10.5 \cr & \Rightarrow \frac{{10000}}{{79x}} - \frac{{100}}{x} = 10.5 \cr & \Rightarrow 10000 - 7900 = 10.5 \times 79x \cr & \Rightarrow x = \frac{{2100}}{{10.5 \times 79}} \cr} $$
∴ Reduced price :
$$\eqalign{ & = {\text{Rs}}{\text{. }}\left( {\frac{{79}}{{100}} \times \frac{{2100}}{{10.5 \times 79}}} \right){\text{ per kg}} \cr & = {\text{Rs}}{\text{. 2 per kg}} \cr} $$
44
If X is 90% of Y, then what percent of X is Y ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & X = \frac{{90}}{{100}}Y \cr & \Rightarrow X = \frac{9}{{10}}Y \cr & \Rightarrow Y = \frac{{10}}{9}X \cr & \Rightarrow \frac{Y}{X} = \frac{{10}}{9} \cr} $$
∴ Required percentage :
$$\eqalign{ & = \left( {\frac{Y}{X} \times 100} \right)\% \cr & = \left( {\frac{{10}}{9} \times 100} \right)\% \cr & = 111\frac{1}{9}\% \cr} $$
45
30% apples out of 450 are rotten, How many apples are in good condition ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Number of rotten apples :
$$\eqalign{ & = 30\% {\text{ of }}450 \cr & = \left( {\frac{{30}}{{100}} \times 450} \right) \cr & = 135 \cr} $$
∴ Number of good apples = 450 - 135 = 315
46
Find the value :
3.2% of 500 × 2.4% of ? = 288
Discuss
Answer & Solution
Answer: Option D
Solution:
Let 3.2% of 500 × 2.4% of x = 288
Then,
$$ \Rightarrow \left( {\frac{{32}}{{10}} \times \frac{1}{{100}} \times 500} \right) \times $$     $$\left( {\frac{{24}}{{10}} \times \frac{1}{{100}} \times x} \right)$$   $$ = 288$$
$$\eqalign{ & \Rightarrow 16 \times \frac{{3x}}{{125}} = 288 \cr & \Rightarrow x = \frac{{288 \times 125}}{{16 \times 3}} \cr & \Rightarrow x = 750 \cr} $$
47
76% of the students in a school are boys. If the number of girls is 204, then the total number of students is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the total number of students be x
Then,
$$\eqalign{ & \left( {100 - 76} \right)\% {\text{ of }}x = 204 \cr & \Rightarrow 24\% {\text{ of }}x = 204 \cr & \Rightarrow \frac{{24}}{{100}}x = 204 \cr & \Rightarrow x = \left( {\frac{{204 \times 100}}{{24}}} \right) \cr & \Rightarrow x = 850 \cr} $$
48
1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Total number of students :
= 1100 + 700
= 1800
Number of students passed :
= (42% of 1100 + 30% of 700)
= (462 + 210)
= 672
Number of failures :
= 1800 - 672
= 1128
∴ Percentage failure :
= $$\left( {\frac{{1128}}{{1800}} \times 100} \right)\% $$
= $$62\frac{2}{3}\% $$
49
If a number is reduced by 40% it becomes two-thirds of another number. What is the ratio of the first number to the second number ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the numbers be $$x$$ and $$y$$ respectively
Then,
60% of $$x$$ = $$\frac{{2}}{{3}}$$ $$y$$
⇒ $$\frac{{60}}{{100}}$$ $$x$$ = $$\frac{{2}}{{3}}$$ $$y$$
⇒ $$\frac{{3}}{{5}}$$ $$x$$ = $$\frac{{2}}{{3}}$$ $$y$$
⇒ $$\frac{{x}}{{y}}$$ = $$\frac{{2}}{{3}}$$ × $$\frac{{5}}{{3}}$$
⇒ $$\frac{{x}}{{y}}$$ = $$\frac{{10}}{{9}}$$
∴ x : y = 10 : 9
50
In a mixture of milk and water, the proportion of water by weight was 75%. If in the 60 gm mixture 15 gm of water was added, what would be the percentage of water ?
Discuss
Answer & Solution
Answer: Option E
Solution:
Weight of water in 60 gm mixture :
= 75% of 60 gm
= $$\left( {\frac{{75}}{{100}} \times 60} \right)$$   gm
= 45 gm
Weight of water in 75 gm mixture :
= (45 + 15) gm
= 60 gm
∴ Required percentage :
= $$\left( {\frac{{60}}{{75}} \times 100} \right)$$   %
= 80%