ExamVeda
Login
Home

Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-6 section-4

Each section contains 100 MCQs on Percentage .
51
The population of a variety of tiny bush in an experimental field increased by 10% in the first year, increased by 8% in the second year but decreased by 10% in the third year. If the present number of bushes in the experimental field is 26730, then the number of bushes in the beginning was :
Discuss
Answer & Solution
Answer: Option A
Solution:
Number of bushes in the beginning :
$$\eqalign{ & = \frac{{26730}}{{\left( {1 + \frac{{10}}{{100}}} \right)\left( {1 + \frac{8}{{100}}} \right)\left( {1 - \frac{{10}}{{100}}} \right)}} \cr & = \left( {26730 \times \frac{{10}}{{11}} \times \frac{{25}}{{27}} \times \frac{{10}}{9}} \right) \cr & = 25000 \cr} $$
52
From a container having pure milk, 20% is replaced by water and the process is repeated thrice. At the end of the third operation, the milk is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let total quantity of original milk = 1000 gm
Milk after first operation = 80% of 1000 = 800 gm
Milk after second operation = 80% of 800 = 640 gm
Milk after third operation = 80% of 640 = 512 gm
∴ Strength of final mixture = 51.2%
53
How much $$66\frac{2}{3}$$% of Rs. 312 exceeds Rs. 200 ?
Discuss
Answer & Solution
Answer: Option C
Solution:
$$66\frac{2}{3}$$% of Rs. 312/- exceeds Rs. 200 by Rs. $$x$$
According to the question, required difference
$$\eqalign{ & x = {\text{Rs}}{\text{. }}\left( {312 \times \frac{{200}}{3}\% - 200} \right) \cr & x = {\text{Rs}}{\text{. }}\left( {312 \times \frac{{200}}{{3 \times 100}} - 200} \right) \cr & x = {\text{Rs}}{\text{. }}\left( {312 \times \frac{{200}}{{300}} - 200} \right) \cr & x = {\text{Rs}}{\text{. }}\left( {208 - 200} \right) \cr & x = {\text{Rs}}{\text{. 8}} \cr} $$
54
Find the number : 125% of 3060 - 85% of (?) = 408
Discuss
Answer & Solution
Answer: Option D
Solution:
Let 125% of 3060 - 85% of x = 408
Then,
$$\eqalign{ & 85\% {\text{ of }}x = \left( {\frac{{125}}{{100}} \times 3060} \right) - 408 \cr & \Rightarrow \frac{{85}}{{100}}x = 3825 - 408 \cr & \Rightarrow \frac{{17x}}{{20}} = 3417 \cr & \Rightarrow x = \left( {\frac{{3417 \times 20}}{{17}}} \right) \cr & \Rightarrow x = 4020 \cr} $$
55
David and his wife each receives an 8 percent annual rise. If David receives a raise of Rs. 800 and his wife receives a raise of Rs. 840, what is the difference between their annual incomes after their raises ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let David's annual income be Rs. x and his wife's annual income be Rs. y
Then,
8% of x = 800
⇒ $$\frac{8}{100}$$x = 800
⇒ x = $$\left( {\frac{{800 \times 100}}{{8}}} \right)$$
⇒ x = 10000
And, 8% of y = 840
⇒ $$\frac{8}{100}$$y = 840
⇒ y = $$\left( {\frac{{840 \times 100}}{{8}}} \right)$$
⇒ y = 10500
∴ Required difference :
= [(10500 + 840) - (10000 + 800)]
= Rs. (11340 - 10800)
= Rs. 540
56
The price of a car is Rs. 325000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Amount paid to car owner = 90% of 85% of Rs. 325000
= Rs. $$\left( {\frac{90}{{100}} \times \frac{85}{100} \times 325000} \right)$$
= Rs. 248625
∴ Required difference :
= Rs. (325000 - 248625)
= Rs. 76375
57
In an election, a total of 500000 voters participated. A candidate got 255000 votes which was 60% of total valid votes. What was the percentage of invalid votes :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the number of valid votes be x
Then,
60% of x = 255000
⇒ x = $$\left( {\frac{{255000 \times 100}}{{60}}} \right)$$
⇒ x = 425000
Number of invalid votes :
= (500000 - 425000)
= 75000
∴ Required percentage :
= $$\left( {\frac{{75000 \times 100}}{{500000}}} \right)$$    %
= 15%
58
If x 80% of y, then what percent of 2x is y ?
Discuss
Answer & Solution
Answer: Option B
Solution:
x = 80% of y
⇒ x = $$\frac{80}{100}$$y
⇒ $$\frac{y}{x}$$ = $$\frac{5}{4}$$
⇒ $$\frac{y}{2x}$$ = $$\frac{5}{8}$$
∴ Required percentage :
$$\eqalign{ & = \left( {\frac{y}{{2x}} \times 100} \right)\% \cr & = \left( {\frac{5}{8} \times 100} \right)\% \cr & = 62\frac{1}{2}\% \cr} $$
59
5 kg of tea and 8 kg of sugar together cost Rs. 172. The price of tea has risen by 20% and that of sugar by 10%. Hence the same quantities of tea and sugar now cost Rs. 199.20. What is the original price of tea per kg ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the original price of tea be Rs. x per kg and that of sugar be Rs. y per kg
Then,
5x + 8y = 172
⇒ 15x + 24y = 516.....(i)
And, 120% of 5x + 110% of 8y = 199.20
⇒ 600x + 880y = 19920
⇒ 15x + 22y = 498 .....(ii)
Subtracting (ii) from (i), we get 2y = 18 or y = 9
Putting y = 9 in (i), we get: x = 20
60
The charges for a five-day trip by a tourist bus for one full ticket and a half-ticket are Rs. 1440 inclusive of boarding charges which are same for a full ticket and a half-ticket. The charges for the same trip for 2 full tickets and one half-ticket inclusive of boarding charges are Rs. 2220. The fare for a half-ticket is 75% of the full ticket. Find the fare and the boarding charges separately for one full ticket.
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the fare for a full ticket be Rs. x and the boarding charges be Rs. y per ticket.
Then, fare for a half-ticket :
= 75% of Rs. x = Rs. $$\frac{3x}{4}$$
$$\eqalign{ & \therefore \left( {x + y} \right) + \left( {\frac{3}{4}x + y} \right) = 1440 \cr & \Rightarrow \frac{{7x}}{4} + 2y = 1440 \cr & \Rightarrow 7x + 8y = 5760 ..... (i) \cr & {\text{And, 2}}\left( {x + y} \right) + \left( {\frac{3}{4}x + y} \right) = 2220 \cr & \Rightarrow \frac{{11x}}{4} + 3y = 2220 \cr & \Rightarrow 11x + 12y = 8880 ..... (ii) \cr} $$
Solving (i) and (ii), we have, x = 480, y = 300