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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-7 section-5

Each section contains 100 MCQs on Percentage .
61
1.14 expressed as a percent of 1.9 is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Required percentage :
$$\eqalign{ & = \left( {\frac{{1.14}}{{1.9}} \times 100} \right)\% \cr & = \left( {\frac{{114}}{{190}} \times 100} \right)\% \cr & = 60\% \cr} $$
62
42% of a number is 892.5. What is 73% of that number ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the number be x
Then,
$$\eqalign{ & 42\% \,\,{\text{of}}\,\,x = 892.50 \cr & \Rightarrow \frac{{42x}}{{100}} = 892.50 \cr & \Rightarrow x = \left( {\frac{{892.5 \times 100}}{{42}}} \right) \cr & \Rightarrow x = 2125 \cr & \therefore 73\% \,\,{\text{of}}\,\,2125 \cr & = \left( {\frac{{73}}{{100}} \times 2125} \right) \cr & = 1551.25 \cr} $$
63
A toy merchant announces 25% rebate in prices of balls. If one needs to have a rebate of Rs. 40, then how many balls each costing Rs. 32, he should purchase ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Rebate on one ball :
= 25% of Rs. 32
= Rs. $$\left( {\frac{{25}}{{100}} \times 32} \right)$$
= Rs. 8
∴ Required number of balls :
= $$\frac{40}{8}$$
= 5
64
Solve this :
85% of 485.5 = 50% of ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Lets 85% of 485.5 = 50% of x
Then,
$$\eqalign{ & \Rightarrow \left( {\frac{{85}}{{100}} \times 485.5} \right) = \frac{{50x}}{{100}} \cr & \Rightarrow \frac{x}{2} = 412.675 \cr & \Rightarrow x = 825.35 \cr} $$
65
Vinay decided to donate 5% of his salary. On the day of donation he changed his mind and donated Rs. 1687.50, which was 75% of what he had decided earlier. How much is Vinay's salary ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let Vinay's salary be Rs. $$x$$
Then,
75% of 5% of $$x$$ = 1687.50
⇒ $$\frac{75}{100}$$ × $$\frac{5}{100}$$ × $$x$$ = 1687.50
⇒ $$x$$ = $$\left( {\frac{{1687.50 \times 100 \times 100}}{{75 \times 5}}} \right)$$
⇒ $$x$$ = 45000
66
64% of a number is 2592. What is 88% of that number ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the number be x
Then,
64% of x = 2592
⇒ $$\frac{64x}{100}$$ = 2592
⇒ x = $$\left( {\frac{{2592 \times 100}}{{64}}} \right)$$
⇒ x = 4050
∴ 88% of 4050 :
= $$\left( {\frac{{88}}{{100}} \times 4050} \right)$$
= 3564
67
Rajan got 76 percent marks and Sonia got 480 marks in a test. The maximum marks of the test equal to the marks obtained by Rajan and Sonia together. How many marks did Rajan score in the test ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the maximum marks be $$x$$
Then,
76% of $$x$$ + 480 = x
⇒ $$x$$ - 76% of $$x$$ = 480
⇒ 24% of $$x$$ = 480
⇒ $$\frac{24x}{100}$$ = 480
⇒ $$x$$ = $$\left( {\frac{{480 \times 100}}{{24}}} \right)$$
⇒ $$x$$ = 2000
∴ Marks score by Rajan :
= 76% of 2000
= $$\left( {\frac{{76}}{{100}} \times 2000} \right)$$
= 1520
68
30% of 28% of 480 is the same as
Discuss
Answer & Solution
Answer: Option D
Solution:
Clearly, 60% of 28% of 240 :
$$\eqalign{ & = \left( {\frac{{60}}{{100}} \times \frac{{28}}{{100}} \times 240} \right) \cr & = \left( {\frac{{30}}{{100}} \times \frac{{28}}{{100}} \times 2 \times 240} \right) \cr & = \left( {\frac{{30}}{{100}} \times \frac{{28}}{{100}} \times 480} \right) \cr & = 30\% \,\,{\text{of}}\,\,285\% \,\,{\text{of}}\,\,480 \cr} $$
69
To meet a government requirement, a bottler must test 5 percent of its spring water and 10 percent of its sparkling water for purity. If a customer ordered 120 cases of spring water and 80 cases of sparkling water, then what percent of all the cases must the bottler test before he can send it out ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Number of cases required to be tested :
$$\eqalign{ & = 5\% \,\,{\text{of}}\,\,120 + 10\% \,\,{\text{of}}\,\,80 \cr & = \left( {\frac{5}{{100}} \times 120} \right) + \left( {\frac{{10}}{{100}} \times 80} \right) \cr & = 6 + 8 \cr & = 14 \cr} $$
∴ Required percentage :
$$\eqalign{ & = \left( {\frac{{14}}{{120 + 80}} \times 100} \right)\% \cr & = \left( {\frac{{14}}{{200}} \times 100} \right)\% \cr & = 7\% \cr} $$
70
A 14.4 kg gas cylinder runs for 104 hours when the smaller burner on the gas stove is fully opened while it runs for 80 hours when the larger burner on the gas stove is fully opened. Which of these value is the closest to the percentage difference in the usage of gas per hour, of the smaller burner over the larger burner ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Consumption of gas in the smaller burner in 1 hour :
$$\eqalign{ & = \left( {\frac{{14.4}}{{104}}} \right){\text{kg}} \cr & = \frac{9}{{65}}{\text{kg}} \cr} $$
Consumption of gas in the larger burner in 1 hour :
$$\eqalign{ & = \left( {\frac{{14.4}}{{80}}} \right){\text{kg}} \cr & = \frac{9}{{50}}{\text{kg}} \cr} $$
Difference in consumption :
$$\eqalign{ & = \left( {\frac{9}{{50}} - \frac{9}{{65}}} \right){\text{kg}} \cr & = \frac{{27}}{{650}}{\text{kg}} \cr} $$
Required percentage difference :
$$\eqalign{ & {\text{ = }}\left( {\frac{{27}}{{650}} \times \frac{{50}}{9} \times 100} \right)\% \cr & = \left( {\frac{{300}}{{13}}} \right)\% \cr & = 23.07\% \cr} $$