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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-7 section-6

Each section contains 100 MCQs on Percentage .
61
A shopkeeper bought 20 kg of rice at Rs. 55 per kg, 25 kg of rice at Rs. 50 per kg, and 35 kg of rice at Rs. 60 per kg. He spent a sum of Rs. 150 on transportation. He mixed all the three types of rice and sold all the stock at Rs. 62.56 per kg. His profit percent in the entire transaction is:
Discuss
Answer & Solution
Answer: Option A
Solution:
Rs. 55 per kg → 20 kg Rice
Rs. 50 per kg → 25 kg Rice
Rs. 60 per kg → 35 kg Rice
55 × 20 = Rs. 1100
50 × 25 = Rs. 1250
60 × 35 = $$\underline {\,{\text{Rs}}{\text{. 2100}}\,} $$
             = Rs. 4450 + Rs. 150
Total Rice 80 kg → Rs. 4600
1 kg → Rs. 57.50
62.56
57.50
$$\overline {\,\,\,5.06\,} $$
$$\frac{{5.06}}{{57.5}}$$  × 100 = 8.8%
62
The monthly salary of a person was Rs. 75,000. He used to spend on Family Expenses (E), Taxes (T), Charity (C) and rest were his savings. E was 60% of the income, T was 20% of E, and C was 15% of T. When his salary got raised by 40% he maintained the percentage level of E, but T became 30% of E and C became 20% of T. The ratio of the saving of his earlier salary to that of his present salary is:
Discuss
Answer & Solution
Answer: Option A
Solution:
Let total income = 100
E = 60
T = 12
C = 1.8
Saving = 100 - 73.8 = 26.2
After increase income = 140
E = 84
T = 25.2
C = 5.04
Saving = 140 - (114.24) = 25.76
Ratio = 26.2 : 25.76
         = 2620 : 2576
         = 655 : 644
63
If 49% of X = Y, then Y% of 50 is:
Discuss
Answer & Solution
Answer: Option D
Solution:
$$\eqalign{ & \frac{{X \times 49}}{{100}} = Y \cr & \frac{X}{Y} = \frac{{100}}{{49}} \cr & 50 \times Y\% \cr & = \frac{{2 \times 50 \times 49\% }}{2} \cr & = \frac{{100 \times 49\% }}{2} \cr & = X \times 24.5\% \cr} $$
64
In a class, if 60% of the students are boys and the number of girls is 36, then the number of boys is:
Discuss
Answer & Solution
Answer: Option B
Solution:
40% → 36
20% → 18
60% → 54
65
When the price of an item was reduced by 20%, its sale increased by x%. If there is an increase of 25% in receipt of the revenue, then the value of x is:
Discuss
Answer & Solution
Answer: Option C
Solution:
$$20\% = \frac{1}{5}$$
\[\begin{array}{*{20}{c}} {}&{{\text{Price}}}&{{\text{Total}}}&{{\text{Sales}}}&{} \\ {{\text{Old}} \to }&5&{100}&{\frac{{100}}{5}}&{ = 20} \\ {{\text{New}} \to }&4&{125}&{\frac{{125}}{4}}&{ \,\,\,\,\,\,\, = 31.25} \end{array}\]
$$\eqalign{ & {\text{Increase in sale}} = 31.25 - 20 = 11.25 \cr & {\text{Increase }}\% = \frac{{11.25}}{{20}} \times 100 = 56.25\% \cr} $$
66
A student multiplied a number with $$\frac{3}{4}$$ instead of $$\frac{4}{3}.$$ What is the error percentage?
Discuss
Answer & Solution
Answer: Option B
Solution:
$$\eqalign{ & \frac{3}{4},\,\frac{4}{3} \cr & {\text{LCM of 4, 3}} = 12 \cr & {\text{First number}} \cr & = \frac{3}{4} \times 12 = 9 \cr & {\text{Second number}} \cr & = \frac{4}{3} \times 12 = 16 \cr & {\text{Error percentage}} \cr & = \frac{7}{{16}} \times 100 = 43\frac{3}{4}\% = 43.75\% \cr} $$
67
A person saves $$33\frac{1}{3}\% $$  of his income. If the saving increases by 22% and the expenditure increases by 10%, then the percentage increase in his income is:
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & 33\frac{1}{3}\% = \frac{1}{3} \cr & {\text{Let income}} = 300 \cr & {\text{Saving}} = 100 \cr & {\text{Expenditure}} = 300 - 100 = 200 \cr} $$
\[\begin{array}{*{20}{c}} {}&{{\text{Income}}}& = &{{\text{Expenditure}}}& + &{{\text{Saving}}} \\ {{\text{Old}} \to }&{300}& = &{200}& + &{100} \\ {}&{}&{}&{\,\,\,\,\,\,\,\,\,\,{ \downarrow ^{ + 10\% }}}&{}&{\,\,\,\,\,\,\,\,\,\,{ \downarrow ^{ + 22\% }}} \\ {{\text{New}} \to }&x& = &{220}& + &{122} \end{array}\]
$$\eqalign{ & x = 220 + 122 = 342 \cr & {\text{Increase}} = 342 - 300 = 42 \cr & {\text{Increase }}\% = \frac{{42}}{{300}} \times 100 = 14\% \cr} $$
68
The sum of weights of A and B is 80 kg. 50% of A's weight is $$\frac{5}{6}$$ times the weight of B. Find the difference between their weights.
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{A}} + {\text{B}} = 80 \cr & {\text{A}} \times \frac{1}{2} = \frac{5}{6}{\text{B}} \cr & \frac{{\text{A}}}{{\text{B}}} = \frac{5}{3} \cr} $$
Percentage mcq question image
$$\eqalign{ & 8\,{\text{unit}} \to 80{\text{ kg}} \cr & 1\,{\text{unit}} \to 10{\text{ kg}} \cr & 2\,{\text{unit}} \to \boxed{20{\text{ kg}}} \cr} $$
69
In an election, candidate X got 70% of the overall valid votes. If 20% of the overall votes were declared invalid and the total numbers of votes is 64000, then find the number of valid votes polled in favour of the candidate.
Discuss
Answer & Solution
Answer: Option A
Solution:
Total vote = 100
Valid vote = 100 - 20 = 80
X = 70% of 80 = 56
100 unit → 64000
1 unit → 640
56 unit → 56 × 640 = 35840
70
In an election between two candidates, 65% of the voters cast their votes, out of which 3% of the votes were decided to be invalid. A candidate got 81965 votes which are 65% of the total valid votes. What is the total number of votes enrolled in that election?
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\eqalign{ & {\text{Valid}} \cr & 65\% \to 81965 \cr & 1\% \to 1261 \cr & 100\% \to 126100 \cr & 65\% {\text{ of }}97\% \to 126100 \cr & 65 \times \frac{{97}}{{100}} \to 126100 \cr & 65\mu \to 130000 \cr & 100\mu \to 200000 \cr} $$