Percentage - Aptitude MCQ Questions and Solutions with Explanations

Let the number of candidates appearing from each state be X.
Then,
7% of X - 6% of X = 80
Or, 1% of X = 80
Or, X = 80 × 100
X = 8000

$$\eqalign{ & {\text{Total number all three got together is}}, \cr & = {1136 + 7636 + 11628} \cr & = 20400 \cr & \% {\text{ of vote the winning candidate got is}}, \cr & = {\frac{{11628}}{{20400}}} \times 100 \cr & = 57\% \cr} $$

Quantity of water in 250 kg dry grapes,
$$ = \frac{{10}}{{100}} \times 250 = 25\,{\text{kg}}$$
Then, pulp of grapes = 225 kg
We get 20 kg pulp in 100 kg fresh grapes.
To get 225 kg pulp , we need fresh grapes,
$${\text{ = }}\frac{{100 \times 225}}{{20}} = 1125\,{\text{kg}}$$

Let the number of bushes originally be 100
Number of bushes after one year
100 ==10% (↑) ==> 110
After second year it becomes
110 ==8%(↑) ==> 118.8
After third year,
118.8 ==8%(↓)==> 109.3
Now, according to the question
109.3 = 26730
1 = $$\frac{{26730}}{{109.3}}$$
So, 100 = $$\frac{{26730}}{{109.3}} \times 100$$    = 25000
Thus, number of bushes originally was 25000

NOTE:
You can take number of bushes originally as x then solve for the x

$$\eqalign{ & \frac{{ {ax} }}{{100}} = \frac{{ {by} }}{{100}} \cr & or,\,ax = by \cr & \Rightarrow y = \frac{{ {ax} }}{b} \cr & c\% \,{\text{of}}\,y = \frac{{ {cy} }}{{100}} \cr & or,\,\frac{{ {cy} }}{{100}} = \frac{{ {cax} }}{{100b}} \cr & {\text{Thus}}, \cr & c\% \,{\text{of}}\,y = \frac{{ca}}{b}\% \,{\text{of}}\,x \cr} $$

Let his original salary be Rs. 100
Salary after increment = Rs. 120
Let the tax on original salary be 20% and now tax on increased salary (Rs. 20) will be 22% i.e. Rs. 4.40
Thus, increase in tax liability $$ = \frac{{4.40}}{{20}} \times 100 = 22\% $$

Let the basic salaries of A and B be x and y respectively.
Now,
$$\eqalign{ & x + 65\% \,\,{\text{of }}x = y + 80\% \,\,{\text{of }}y \cr & \Rightarrow x + \frac{{ {65x} }}{{100}} = y + \frac{{ {80y} }}{{100}} \cr & \Rightarrow \frac{x}{y} = \frac{{180}}{{165}} \cr & \Rightarrow x:y = 12:11 \cr} $$

They covered the distance in this way together in different hours
6 + 6.5 + 7 + 7.5 + 8 + 8.5 + 9 + 9.5 + 10 = 72 Means,they'll meet at the 9^th hr.
So, In that time A will cover = 4 × 9 = 36km
They will meet in Midway

$$\eqalign{ & {\text{Let the number of total workers}} = x \cr & {\text{Number of skilled workers}} \cr & = 75\% \,of\,x = \frac{{75x}}{{100}} = \frac{{3x}}{4} \cr & {\text{No}}{\text{. of unskilled workers}} \cr & = 25\% \,of\,x = \frac{{25x}}{{100}} = \frac{x}{4} \cr & {\text{No}}{\text{. of permanent workers}}, \cr & = {\frac{{80}}{{100}}} \times {\frac{{3x}}{4}} + {\frac{{20}}{{100}}} \times {\frac{x}{4}} \cr & = {\frac{{3x}}{5}} + {\frac{x}{{20}}} \cr & = \frac{{13x}}{{20}} \cr & {\text{No}}{\text{.}}\,{\text{of}}\,{\text{temporary}}\,{\text{workers,}} \cr & = x - {\frac{{13x}}{{20}}} = \frac{{7x}}{{20}} \cr & {\text{Now}}, \cr & \frac{{7x}}{{20}} = 126 \cr & x = 360 \cr} $$

No. of population who are literate = 50% of 296000 = 148000
No. of male = 166000
No. of female = 296000 - 166000 = 130000
No. of literate male = 70% of 166000 = 116200
No. of literate women
= 148000 - 116200
= 31800