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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-9 section-2

Each section contains 100 MCQs on Percentage .
81
The ratio of the number of boys and girls in school at 8 : 12. If 50% of boys and 25% of girls are getting scholarship for their studies, what is the percentage of school students who are not getting any scholarships ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the number of boys is = 8x
Number of girls = 12x
Boys are not getting scholarship
= 8x × $$\frac{1}{2}$$ = 4x
Girls are not getting scholarship
= 12x × $$\frac{3}{4}$$ = 9x
% of students not getting scholarship
= $$\frac{(4x + 9x)}{20x}$$   × 100
= 65%
82
In an examination there were 640 boys and 360 girls, 60% of boys and 80% of were successful. The percentage of failure was :
Discuss
Answer & Solution
Answer: Option D
Solution:
The number of failure boys
= $$\frac{640 × 40}{100}$$
= 256
The number of failure girls
= $$\frac{360 × 20}{100}$$
= 72
Percentage of failure students
= $$\frac{(72 + 256)}{640 + 360}$$
= 32.8%
83
In an election between two candidates, 75% of the voters cast their votes, out of which 2% votes were declared invalid. A candidate got 9261 votes which were 75% of the valid votes. The total number of voters enrolled in that election was :
Discuss
Answer & Solution
Answer: Option C
Solution:
Total valid votes got candidates
= $$\frac{9261}{75}$$ × 100
= 12348
Let total number of votes = x
Total votes polled
= x × $$\frac{75}{100}$$
= $$\frac{75x}{100}$$
Valid votes = $$\frac{75x}{100}$$ × $$\frac{98}{100}$$
According to the question,
⇔ $$\frac{75x}{100}$$ × $$\frac{98}{100}$$ = 12348
⇔ x = 16800
Hence, total votes = 16800
84
1 litre of water is added to 5 litres of alcohol-water solution containing 40% alcohol strength. The strength of alcohol in the new solution will be :
Discuss
Answer & Solution
Answer: Option D
Solution:
40% = $$\frac{{2\,\, \to \,\,{\text{Alcohol}}}}{{5\,\, \to \,\,{\text{Mixture}}}}$$
Water : Alcohol
     3   :   2
Required percentage
= $$\frac{2}{(5 + 1)}$$ × 100
= $$\frac{2}{6}$$ × 100
= $$\frac{1}{3}$$ × 100
= $$33\frac{1}{3}$$%
85
Each side of a rectangular field is diminished by 40%. By how much percent is the area of the field diminished ?
Discuss
Answer & Solution
Answer: Option B
Solution:
By using successive formula
Net decrease in area
$$\eqalign{ & = 40 + 40 - \frac{{40 \times 40}}{{100}} \cr & = 64\% \cr} $$
86
There is a ratio of 5 : 4 between two numbers. If 40% of the first number is 12, then what would be 50% of the second number ?
Discuss
Answer & Solution
Answer: Option A
Solution:
1st number : 2nd number
           5     :     4
40% = $$\frac{2}{5}$$
2 units = 12
5 units = 30
So, 1st number = 30
2nd number = $$\frac{30}{5}$$ × 4 = 24
50% of 2nd = 24 × $$\frac{1}{2}$$ = 12
87
The ratio of number of boys and girls in a school 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1 ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Number of a boy in the school = 720 × $$\frac{7}{12}$$   = 420
Number of a girl in the school = 720 × $$\frac{5}{12}$$   = 300
To maintain 1 : 1 we will have to add number of girls = 420 - 300 = 120
88
On a certain date, Pakistan has a success rate of 60% against India in all the ODI's played between the two countries. The lost the next 30 ODI's. In a row to India and their success rate comes down to 30%. The total number of ODI's played between the two countries is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let a total of 5x match is played between Pakistan and India. Pakistan won 3x matches and India won 2x matches
According to the question,
But now India won 30 matches in a row and hence India's success percentage increase to 70%.
Now, Total match = 5x + 30
(2x + 30) = (5x + 30) × $$\frac{70}{100}$$
20x + 300 = 35x + 210
15x = 90
x = 6
So, total match :
= 5x + 30
= 5 × 6 + 30
= 60 matches
89
A person who spends $$66\frac{2}{3}$$% of his income is able to save Rs. 1200 per month. His monthly expenses (in Rs.) is :
Discuss
Answer & Solution
Answer: Option B
Solution:
$$66\frac{2}{3}$$% = $$\frac{2}{3}$$
Let the income of the person = 3 units
Expenditure = 2 units
Savings = (3 - 2) = 1 unit
According to the question,
1 unit = Rs. 1200
2 units = 2 × 1200 = Rs. 2400
90
The cost of an article worth Rs. 100 is increased by 10% first and again increased by 10%. The total increase in rupees is :
Discuss
Answer & Solution
Answer: Option B
Solution:
% increase = 10 + 10 + $$\frac{10 × 10}{100}$$  = 21%
Total increase = $$\frac{100 × 21}{100}$$  = Rs. 21