ExamVeda
Login
Home
81
A dozen pairs of socks quoted at Rs. 180 are available at discount of 20%. How many pairs of socks can be bought for Rs. 48 ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Price after discount
= $$\frac{180 × 80}{100}$$
= Rs. 144
Price of 1 pair of socks
= Rs. $$\frac{144}{12}$$
= Rs. 12
Required number of pairs
= $$\frac{48}{12}$$
= 4 pairs
82
If the population of a town is 64000 and its annual increase is 10%, then its population at the end of 3 years will be :
Discuss
Answer & Solution
Answer: Option B
Solution:
Present population = 64000
1st year = 66400
2nd year = 6400 + 640
3rd year = 6400 + 2 × 640 + 64

Total population after 3 years
= 64000 + 3 × 6400 + 3 × 640 + 64
= 85184

Alternate:
Population after n years
$$\eqalign{ & \Rightarrow {\text{p}}' = {\text{p}}{\left( {1 \pm \frac{{\text{R}}}{{100}}} \right)^{ \pm {\text{n}}}} \cr & {\text{p}}' = 64000{\left( {1 \pm \frac{{10}}{{100}}} \right)^3} \cr & \,\,\,\,\,\,\,\, = 85184 \cr} $$
83
In a village three people contested for the post of village Pradhan. Due to their own interest, all the voters voted and no one vote was invalid. The losing candidate got 30% votes. What could be the minimum absolute margin of votes by which the winning candidate led by the nearest rival, if each candidate got an integral percent of votes ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Let total votes in village = 100
Losing candidate got votes = 30% of 100 = 30 votes
Winner's and nearer rival's votes
= 100 - $$\frac{13}{100}$$ × 100
= 70
∴ If both get equal votes then, it should be, 35
∴ Minimum difference between winner and nearer rival
= (36 - 34) = 2
84
I paid Rs. 27.20 as sales tax on a watch worth Rs. 340. Find the rate of sales tax.
Discuss
Answer & Solution
Answer: Option A
Solution:
Rate of sales tax
$$\eqalign{ & = \left( {\frac{{27.20}}{{340}} \times 100} \right)\% \cr & = 8\% \cr} $$
85
A student scores 55% marks in 8 papers of 100 marks each. He scores 15% of his total marks in English. How much does he score in English ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Total marks obtained by the student
= 55% of 800
= $$\frac{55}{100}$$ × 800
= 440
∴ Marks scored in English
= 15% of 440
= $$\frac{15}{100}$$ × 440
= 66
86
A wrist watch of cost price Rs. 1250 was sold by Sharel for Rs. 1500. What was the profit percent ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Cost price of wrist watch = Rs. 1250
Sale price of wrist watch = Rs. 1500
Profit percent :
$$\eqalign{ & = \left( {\frac{{1500 - 1250}}{{1250}}} \right) \times 100 \cr & = \frac{{250}}{{1250}} \times 100 \cr & = \frac{{25000}}{{1250}} \cr & = 20\% \cr} $$
87
Ms. Pooja invests 13% of her monthly salary, i.e., Rs. 8554 in Mediclaim Policies. Later she invests 23% of her monthly salary on Child Education Policies; also she invests another 8% of her monthly salary on Mutual Funds. What is the total annual amount invested by Ms. Pooja ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let Pooja's monthly salary be = Rs. x
Then, 13% of x = 8554
⇒ $$\frac{13x}{100}$$ = 8554
⇒ x = $$\frac{8554 × 100}{13}$$
⇒ x = 65800
Total percentage of salary invested
= (13 + 23 + 8)%
= 44%
∴ Total amount invested monthly
= 44% of Rs. 65800
= Rs. $$\frac{44}{100}$$ × 65800
= Rs. 28952
88
The difference of two numbers is 20% of the larger number. If the smaller number is 20, then the larger number is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the larger number be x
Then, x - 20 = $$\frac{20}{100}$$x
⇔ x - $$\frac{1}{5}$$x = 20
⇔ $$\frac{4}{5}$$x = 20
⇔ x = 20 × $$\frac{5}{4}$$
⇔ x = 25
89
Two candidates fought an election. One of them got 62% of the total votes and won by 432 votes. What is the total number of votes polled ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the total number of votes polled be x
Then, votes polled by other candidate
= (100 - 62)% of x
= 38% of x
∴ 62% of x - 38% of x = 432
⇒ $$\frac{24x}{100}$$ = 432
⇒ x = $$\frac{432 × 100}{24}$$
⇒ 1800
90
If x, y, z are three positive integers such that x is greater then y and y is greater than z, then which of the following is definitely true ?
Discuss
Answer & Solution
Answer: Option D
Solution:
(a) x% of y = $$\frac{xy}{100}$$ and y of z = $$\frac{yz}{100}$$
x > y, y < z
⇒ xy > yz
⇒ $$\frac{xy}{100}$$ > $$\frac{yz}{100}$$
⇒ x% of y > y% of z

(b) y% of x = $$\frac{xy}{100}$$ and z% of y = $$\frac{yz}{100}$$
As proved above, y% of x > z% of y

(c) z% of x = $$\frac{xy}{100}$$ and y% of z = $$\frac{yz}{100}$$
x > y
⇒ xz > yz
⇒ $$\frac{xz}{100}$$ > $$\frac{yz}{100}$$
⇒ z% of x > y% of z