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Speed Time And Distance - Aptitude MCQ Questions and Solutions with Explanations

Speed Time And Distance MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Speed Time And Distance with easy and logical explanations. Speed Time And Distance MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-8 section-1

Each section contains 100 MCQs on Speed Time and Distance .
71
A man can row 15 km/h in still water and he finds that it takes him twice as much time to row up than as to row down the same distance in the river. The speed of current (in km/h) :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the speed of the current be x km/h. Now, according to the question,
$$\frac{{15 + x}}{{15 - x}} = \frac{2}{1}$$
15 + x = 30 - 2x
3x = 30 - 15
3x = 15
x = 5 km/h
72
A boat covers 48 km upstream and 72 km downstream in 12 hours, while it covers 72 km upstream and 48 km downstream in 13 hours The speed of stream is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let downstream speed be D and Upstream speed be U. Then
$$\eqalign{ & {\frac{{48}}{U} + \frac{{72}}{D}} = 12\,.\,.\,.\,.\,.\,.\,.\left( 1 \right) \cr & {\text{and}} \cr & {\frac{{72}}{U} + \frac{{48}}{D}} = 13\,.\,.\,.\,.\,.\,.\,.\left( 2 \right) \cr} $$
On solving the equation (1) and (2), we get
D = 12 kmph and
U = 8 kmph
Thus, speed of the current
$$ = \frac{{D - U}}{2} = \frac{4}{2} = 2\,{\text{kmph}}$$
73
A motor boat takes 2 hours to travel a distance of 9 km downstream and it takes 6 hours to travel the same distance against the current. The speed of the boat in still water and that of the current (in km/h) respectively are:
Discuss
Answer & Solution
Answer: Option B
Solution:
Downstream speed,
= $$\frac{9}{2}$$ = 4.5 kmph
Upstream speed,
= $$\frac{9}{6}$$ = 1.5 kmph
Thus, speed of boat in still water,
= $$\frac{{4.5 + 1.5}}{2}$$   = 3 km/h
Speed of current = $$\frac{{4.5 - 1.5}}{2}$$   = 1.5 km/h
74
A train met with an accident 120 km from station A. It completed the remaining journey at $$\frac{5}{6}$$ of its previous speed and reached 2 hour late at station B. Had the accident taken place 300 km further, it would have been only 1 hour late. What is the speed of the train?
Discuss
Answer & Solution
Answer: Option C
Solution:
A ____100 km____ P1 ________300 km_____ P2 ____X______ B

If speed becomes $$\frac{5}{6}$$ then time taken will be $$\frac{6}{5}$$ of original time.
Thus, extra time = 2 hour
$$\frac{1}{5}$$ = 2 hour
Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.
It means It covers 300 km distance in 5 hours.
then speed = $$\frac{{300}}{5}$$ = 60 km/h
75
A runs $$\frac{7}{4}$$ times as fast as B. If A gives B a start of 300 m, how far must the winning post be if both A and B have to end the race at same time?
Discuss
Answer & Solution
Answer: Option B
Solution:
.ABReason (ST=D)
Speed74Given
Time 47Since, Speed ∝ $$\frac{1}{{{\text{Time}}}}$$
Distance4 7Distance ∝ time


Now,
7x - 4x = 300 (A runs 7x m and B runs 4x)
x = 100
7x = 7 × 100 = 700 m
Winning post is 700 m away, As A runs 700 m to complete the race.
76
The wheel of an engine of 300 cm in circumference makes 10 revolutions in 6 seconds. What is the speed of the wheel (in km/h)?
Discuss
Answer & Solution
Answer: Option A
Solution:
Circumference = One revolution
Distance covered in 10 revolutions = 300 * 10 = 3000 cm = 30 m
30 meters are covered in 6 seconds.
Speed of the wheel = $$\frac{{30}}{{\text{6}}}$$ = 5 m/s
5 m/s = $$\frac{{5 \times 18}}{5}$$  = 18 km/h. [ To convert m/s to km/h, we use to multiply by factor $$\frac{{18}}{5}$$ ]
77
A thief sees a jeep at a distance of 250 m, coming towards him at 36 km/h. Thief takes 5 seconds to realize that there is nothing but the police is approaching him by the jeep and start running away from police at 54 km/h. But police realise after 10 second, when the thief starts running away, that he is actually a thief and gives chase at 72 km/h. How long after thief saw police did catchup with him and what is the distance police had travel to do so?
Discuss
Answer & Solution
Answer: Option B
Solution:
Initial speed of the police = 10 m/s
Increased speed of the Police = 20 m/s
Speed of the thief = 15 m/s
Initial difference between speed of thief and police = 250 m
After 5 seconds difference between thief and police = 200 + (5 × 10) = 250 m
Now, the time required by police to catch the thief = $$\frac{{250}}{5}$$ = 50 s
Total time = 50 + 15 = 65 s
Total distance = 1000 + (15 × 10) = 1150 m.
78
A person X starts from Lucknow and another person Y starts from Kanpur to meet each other. Speed of X is 25 km/h, while Y is 35 km/h. If the distance between Lucknow and Kanpur be 120 km and both X and Y start their journey at the same time, when they will meet ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Lucknow(X →)_____120 km _____(← Y)Kanpur

Relative speed = (25+35) = 60 km/h
Time taken to complete 120 km,
= $$\frac{{120}}{{60}}$$ = 2 h
Thus, They will meet 2 hours later.
79
Two persons A and B started from two different places towards each other. If the ratio of their speed be 3 : 5, then what is the ratio of distance covered by A and B respectively till the point of meeting?
Discuss
Answer & Solution
Answer: Option C
Solution:
When time is constant the distance covered by A and B will be in the ratio of their speeds. i.e. ratio of distance is 3 : 5 as time is constant.
80
The ratio of speeds of A and B is 2 : 3 and therefore A takes 20 minutes more time than B. What is the ratio of time taken by A and B?
Discuss
Answer & Solution
Answer: Option C
Solution:
When distance is constant then Speed is inversely proportional to time.
ST = D
When distance constant,
S ∝ $$\frac{1}{{\text{T}}}$$
So, ratio of time taken by A and B = 3 : 2