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Time And Work - Aptitude MCQ Questions and Solutions with Explanations

Time And Work MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Time And Work with easy and logical explanations. Time And Work MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-4 section-1

Each section contains 100 MCQs on Time and Work .
31
Raj can do a piece of work in 20 days. He started the work and left after some days, when 25% work was done. After it Abhijit joined and completed it working for 10 days. In how many days Raj and Abhijit can do the complete work, working together?
Discuss
Answer & Solution
Answer: Option B
Solution:
Efficiency of Raj = $$\frac{{100}}{{20}}$$ = 5%
Work completed by Raj = 25%
Rest work = 75%
Efficiency of Abhijit = $$\frac{{75}}{{10}}$$ = 7.5%
Combined efficiency = 5 + 7.5 = 12.5%
They will complete the whole work by working together in,
= $$\frac{{100}}{{12.5}}$$ = 8 days
32
If 10 persons can do a job in 20 days, then 20 person with twice the efficiency can do the same job in:
Discuss
Answer & Solution
Answer: Option A
Solution:
By work equivalence method,
man × days × work = MAN × DAYS × WORK
10 × 20 × 1 = 20 × 2 × x
→ x = 5 days
33
There was a leakage in the container of the refined oil. If 11 kg oil is leaked out per day then it would have lasted for 50 days, if the leakage was 15 kg per day, then it would have lasted for only 45 days. For how many days would the oil have lasted, if there was no leakage ant it was completely used for eating purpose?
Discuss
Answer & Solution
Answer: Option B
Solution:
Let x kg of oil be used for the eating purpose, daily, then
(x + 11) × 50 = (x +15) × 45
→ x = 25
Thus, Total quantity of oil,
= (25 +11) × 50
= 1800
Hence, required number of days,
= $$\frac{{1800}}{{25}}$$  = 72 days
34
If 2 men or 3 women or 4 boys can do a piece of work in 52 days, then the same piece of work will be done by 1 man, 1 woman and 1 boy in:
Discuss
Answer & Solution
Answer: Option A
Solution:
Work done by 2 men = 3 women = 4 boys
1 man = 2 boys
1 woman = $$\frac{4}{3}$$ boys
Thus,
Boys × days = 4 × 52 boys × days
Again,
1 man + 1 women + 1 boys,
$$ = 2 + \frac{4}{3} + 1$$
$$ = \frac{{13}}{3}$$  boys
Using work equivalent method,
boys × day = BOYS × DAYS
$$4 \times 52 = \frac{{13}}{3} \times {\text{x}}\,{\text{(let)}}$$
x = 48 days
35
If one pipe A can fill a tank in 20 minutes, then 5 pipes, each of 20% efficiency of A, can fill the tank in:
Discuss
Answer & Solution
Answer: Option C
Solution:
Efficiency of pipe A,
$$\frac{{100}}{{20}}$$ = 5%
20% of efficiency of A = 1%
Then, efficiency of 5 such pipes = 5%.
Then,
Time taken to fill the tank = $$\frac{{100}}{5}$$ = 20 min.
36
If m men can do a work in r days, then the number of days taken by (m + n) men to do it is :
Discuss
Answer & Solution
Answer: Option C
Solution:
M1 × D1 = M2 × D2
mr = (m +n) × D2
D2 = $$\frac{{{\text{mr}}}}{{{\text{m}} + {\text{n}}}}$$
37
X takes 4 days to complete one-third of a job. Y takes 3 days to complete one-sixth of the job and Z takes 5 days to complete half the job. If all of them work together for 3 days and X and Z quit, how long will it take for Y to complete the remaining work done.
Discuss
Answer & Solution
Answer: Option C
Solution:
X completes $$\frac{1}{3}$$ rd in 4 days = 33.33% job in 4 days
X One day work = 8.33%
Y one day work = 5.55% [As he complete $$\frac{1}{6}$$ job = 16.66% job in 3 days]
Z one day work = 10%
Work done in 3 days by X, Y and Z
= 25 + 16.66 + 30 = 71.66%
Remaining work will be done by Y in,
$$\frac{{28.33}}{{5.55}}$$  = 5.1 days
38
Two typist of varying skills can do a job in 6 minutes if they work together. If the first typist typed alone for 4 minutes and then the second typist typed alone for 6 minutes, they would be left with $$\frac{1}{5}$$ of the whole work. How many minutes would it take the slower typist to complete the typing job working alone ?
Discuss
Answer & Solution
Answer: Option B
Solution:
Working efficiency of both typist together,
= $$\frac{{100}}{6}$$ = 16.66% per minute

Now, let work efficiency of first typist be x and then second typist will be (16.66 - x)
First typist typed alone for 4 minutes and second typed alone for 6 minutes and they left with $$\frac{1}{5}$$ (i.e 20%) of job, means they have completed 80% job
Now,
First Typist typed in 4 minute + Second typed in 6 minutes = 80%
4 × x + 6 × (16.66 - x) = 80%
4x + 100% - 6x = 80%
x = 10%
First Typist typed 10% per minutes. Then second typed (16.66 - 10) = 6.66% per minute
Then, Second typist complete the whole job in $$\frac{{100}}{{6.66}}$$ = 15.01 = 15 minutes.
39
A and B completed a work together in 5 days. had A worked at twice the speed and B at half the speed, it would have taken them four days to complete the job. How much time would it take for A alone to do the work?
Discuss
Answer & Solution
Answer: Option A
Solution:
Assume work to be done 100%.
First case,
A + B = $$\frac{{100}}{5}$$ = 20% work done per day -------- (1)
Second case,
2A + $$\frac{{\text{B}}}{2}$$ = $$\frac{{100}}{4}$$ = 25% work done per day ------ (2)
On solving equation (1) and (2), we get
A = 10 days
40
Two forest officials in their respective division were involved in the harvesting of tendu leave. One division had an average output of 21 tons from a hectares and other division, which had 12 hectares of land less, dedicated to tendu leaves, got 25 tons of tendu from a hectare. As a result, the second division harvested 300 tons of tendu leaves more than the first. How many tons of tendu leaves did the first division harvest.
Discuss
Answer & Solution
Answer: Option A
Solution:
Let First division have x hectare of the land then second division will have (x - 12) hectare of land
Now according to the question,
25 × (x - 12) = 21x + 300
or, x = 150 hectare
Hence, the first division harvest 3150 tons tendu leaves.