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1
In a two dimensional incompressible steady flow around an airfoil, the stream lines are 2 cm apart at a great distance from the airfoil, where the velocity is 30 m/sec. The velocity near the airfoil, where the stream lines are 1.5 cm apart, is
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Answer & Solution
Answer: Option C
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2
According to the principle of buoyancy a body totally or partially immersed in a fluid will be lifted up by a force equal to
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Answer & Solution
Answer: Option D
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3
The difference of pressure between the inside and outside of a liquid drop is
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Answer & Solution
Answer: Option D
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4
Fluid is a substance that
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Answer & Solution
Answer: Option D
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5
The line of action of the buoyant force acts through the
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Answer & Solution
Answer: Option D
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6
A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5 m and 6.0 m res-pectively below the free surface. The position of center of pressure below the free surface will be at a distance of
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Answer & Solution
Answer: Option C
Solution:
Understanding the Problem:
We need to find the center of pressure on a rectangular surface submerged in water.
The center of pressure is the point where the total hydrostatic force acts on the surface.
Key Concepts:
For a vertically submerged rectangle, the center of pressure (hcp) is located below the centroid (center of area).
The formula to calculate hcp is: hcp = hc + (Ixx / (A * hc))
Where:
hc is the depth of the centroid from the free surface.
Ixx is the second moment of area (moment of inertia) about the centroidal axis.
A is the area of the submerged surface.
Step-by-Step Solution:
1. Find the depth of the centroid (hc):
The rectangle's top is at 1.5 m and the bottom is at 6.0 m.
The height of the rectangle is 6.0 m - 1.5 m = 4.5 m.
The centroid is located at the middle of the rectangle's height.
So, hc = 1.5 m + (4.5 m / 2) = 1.5 m + 2.25 m = 3.75 m
2. Calculate the Area (A):
We are not given the width (b) of the rectangle so we consider it as b.
Height of the rectangle h = 4.5 m
A = b * h = b * 4.5 m
3. Calculate the Moment of Inertia (Ixx):
For a rectangle about its centroidal axis, Ixx = (b * h3) / 12.
Ixx = (b * (4.5)3) / 12 = (b * 91.125) / 12
4. Calculate the Center of Pressure (hcp):
hcp = hc + (Ixx / (A * hc))
hcp = 3.75 + (((b * 91.125) / 12) / ((b * 4.5) * 3.75))
hcp = 3.75 + ((b * 91.125) / 12) / (b * 16.875)
hcp = 3.75 + (91.125 / 12) / 16.875 (b cancels out)
hcp = 3.75 + (7.59375 / 16.875)
hcp = 3.75 + 0.45
hcp = 4.2 m
Therefore, the correct answer is Option C: 4.2 m.
7
An object having 10 kg mass weighs 9.81kg on a spring balance. The value of ‘g’ at this place is
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Answer & Solution
Answer: Option B
Solution:
Weight (W) is the force exerted by gravity on an object and is given by the formula W = m * g
Here, the mass (m) of the object is 10 kg
The weight of the object as measured by the spring balance is 9.81 kg (which is actually a measure of force in newtons but given in kg for simplicity)
To find the acceleration due to gravity (g) at this place, we use the formula:
g = W / m
Substituting the given values:
g = 9.81 kg / 10 kg
g = 9.81 m/sec2
Therefore, the value of 'g' at this place is 9.81 m/sec2
8
The region between the separation streamline and the boundary surface of the solid body is known as
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Answer & Solution
Answer: Option A
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9
Steady flow occurs when
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Answer & Solution
Answer: Option B
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10
The shear stress distribution for a fluid flowing in between the parallel plates, both at rest, is
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Answer & Solution
Answer: Option C
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