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Find the selling price of goods if two salesmen claim to make 25% profit each, one calculating it on cost price while another on the selling price, the difference in the profits earned being Rs. 100 and selling price being the same in both the cases?
Answer & Solution
Correct Answer:
Option
A
Let CP's be Rs. 1000 each, their respective SP will be,
1000 == 25%↑ ⇒ 1250 [person calculating profit on the CP]
1000 == 33.33%↑ ⇒ 1333.33 [The person calculating his profit on SP: 25% of SP = 33.33% of CP]
The difference turned out to be = 83.33. This has occured when we have assumed the CP as 1000. But, we are given difference of Rs. 100
So, on comparing,
83.33 = 1000
1 = $$\frac{{1000}}{{83.33}}$$
100 = $$\frac{{1000}}{{83.33}} \times 100$$ = Rs. 1200
1000 == 25%↑ ⇒ 1250 [person calculating profit on the CP]
1000 == 33.33%↑ ⇒ 1333.33 [The person calculating his profit on SP: 25% of SP = 33.33% of CP]
The difference turned out to be = 83.33. This has occured when we have assumed the CP as 1000. But, we are given difference of Rs. 100
So, on comparing,
83.33 = 1000
1 = $$\frac{{1000}}{{83.33}}$$
100 = $$\frac{{1000}}{{83.33}} \times 100$$ = Rs. 1200
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LoginCP SP P
1) 4 5 1
2) 3 4 1
GIiven that both goods have same SP
1) 4×4 5×4 1×4
2) 3×5 4×5 1×5
1) 16 20 4
2) 15 20 5
Diffrence between profit is 100
But we have, 5-4=1
1= 100
Then 20= 2000
Hence, 2000 is right option.
He takes profit as 25% of CP
CP of SM1= x
SP of SM1 = y
x + 25%x = y..............................................(A)
125%x = y
y = 125x/100
y = 5x/4.................................................(1)
Sales man 2 (SM2) :-
He takes profit as 25% of SP
CP of SM2 = z
SP of SM2 = y (because selling prices of two sales man are same)
z + 25%y = y.......................................(B)
z + 25y/100 = y
z + y/4 = y
z = y - y/4
z = 3y/4
y = 4z/3...........................................(2)
equate (1) and (2)
5x/4 = 4z/3
x/z = 16/15
So, x/z = 16a/15a ( create new variable "a" because we didn't know the correct value)
x = 16a
z = 15a
substitute x in (A)
16a + 25% (16a) = y
y = 16a + 4a ( here "4a" is profit for SM1)
y = 20a
substitute y, z in (B)
15a + 25% (20a) = 20a
15a + 5a = 20a ( here "5a" is profit for SM2)
Difference between profit of two sales mans is 100
So, 5a - 4a = 100
a = 100
Then,
y = 20a = 20 (100) = 2000
x = 16a = 16 (100) = 1600
z = 15a = 15 (100) = 1500
But according to question It's answer should be 2000
given gain = 25% = 1/4
now case 1 , calculating profit on cp.
let cp= 4x so profit = 4x*1/4=x so sp= 4x+x=5x
now case 2, calculating on sp
let sp=4y so profit = y
now ATQ
5x=4y and y-x=100, solve eq. you get x=400 so sp =5x=5*400=2000
And the selling price is
1000 + 25% of 1000 = 1250.
Now, 25% of 1250 = 312.5.
25% = 312.5
So, 100% = 1333.33
Thus, the actual profit on the Cost price would be,
(333.33*100)/1000 = 33.33%.
Now, Is it clear @Divya?