ExamVeda
Login
Home
81
If a binary system exihibits a miscibility gap in the solid state, then the enthalpy of mixing in the solid state, ΔHmix should necessarily be
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
82
The vapour pressure of a solid M varies with temperature T in K, as
In p(atm) = $$\frac{{ - 33,200}}{T}$$ - 0.85 In T + 21.46
The vapour pressure of liquid M varies with temperature T, in K, as
In p (atm) $$\frac{{ - 33,200}}{T}$$ = 0.85 In T + 20.31
The temperature of the triple point of M, in K is
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
83
The units of the rate constant for it second order reaction are
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
84
The activity co-efficient of the solute in a dilute solution
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
85
The expression for gas law is
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
86
The limiting condition for the appearance of the miscibility gap in a binary solution is
Where, G is the Gibbs free energy and X is the mole fraction of component Z.
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
87
As the concentration of point defects in a crystal increases, its configurational entropy
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
88
For a first order chemical reaction the concentration of the reactant decreases
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
89
Which of the following- properties is Intensive?
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
90
FeO(s) + CO(g) = Fe(s) + CO2(g); K = 0.435 at 1173 K. At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173K?
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board