Metallurgical Thermodynamics and Kinetics MCQ Questions and Answers | Metallurgical Engineering
Enhance your knowledge of Metallurgical Thermodynamics and Kinetics with this comprehensive collection of MCQ questions and answers. These MCQ questions and answers in Metallurgical Thermodynamics and Kinetics are specifically designed for students of Metallurgical Engineering who are preparing for the GATE Exam. Strengthen your preparation and excel in your studies with this valuable resource. Page-10 section-1
Each section contains 100 MCQs on
Metallurgical Thermodynamics and Kinetics .
AG(s) = Ag(l), T = 1234K; ΔH = 11300 J.mol-1 ΔCP = Cp(l) - Cp(s) = 0
When one mole of super cooled liquid silver freezes at an ambient temperature of 1000 K, the total entropy change of the system (Ag) and the surroundings is . . . . . . . . J.K-1.
For the reaction, A = X + Y, the respective concentrations are CA, CX and CY. The forward reaction rate constant is kf and the backward reaction rate constant is kb. Choose the correct statement from the following:
P. At equilibrium, kf CA > kB CxCy
Q. If the reaction is irreversible than, kb CXCY = 0
R. The backward reaction rate will essentially be first order, if the forward reaction rate is first order.
S. Activation energy for the first order forward reaction will be independent of temperature.
If, $$Y = {k_1}\left[ {1 - \exp \left( {\frac{{{k_2}\Delta x}}{{{k_3}x}}} \right)} \right],$$ where k1, k2 and k3 are constants. If k2ΔX < ΔX, the value of γ up to first order of approximation would be
Consider the reaction:
Fe3O4 (solid, pure) + CO (gas, 1 atm) → 3FeO (solid, pure) + CO2 (gas, 1 atm)
For this reaction, ΔG1200 = -8000 joules per mole of CO and R = 8.314 J mol-1 K-1.
The equilibrium ratio, $$\frac{{pc{o_2}}}{{pco}}$$ reaction at 1200 K and 1 atm is . . . . . . . .
The activation energy for a reaction is 100 kJ/mole. The approximate increase in temperature required for doubling the rate of reaction from that at 25°C, is . . . . . . . . °C.
For a binary solution A - B, the α-function is given by $$\alpha = \frac{{\exp \left( x \right) - 1}}{X}$$ Where, X is the mole fraction of component A. The limiting value of a when X approaches zero, is
