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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-4 section-3

Each section contains 100 MCQs on Percentage .
31
In an examination, 65% of the students passed in Mathematics, 48% passed in Physics and 30% passed in both. How much percent of students failed in both the subjects ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Pass students in Mathematics = 65%
Pass students in Physics = 48%
Student pass in both subject Mathematics and Physics = 30%
Student only pass in Mathematics = 65 - 30 = 35%
Student only pass in Physics = 48 - 30 = 18%
Percentage of Failed students in both subjects :
= 100 - [ student pass only in Mathematics + student pass only in Physics + student pass in both subject]
= [100 - (35 + 18 + 30)]
= 17%
32
At an election there were two candidate got 38% of votes and lost by 7200 votes. The total numbers of valid votes were :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let the total number of votes = 100x
losser candidate get 38% of vote i.e. = 38x and winner will get = 100x - 38x = 62x
According to the question,
62x - 38x = 7200
⇒ 24x = 7200
⇒ x = 300
Total votes = 100x
= 100 × 300
= 30000
33
In 2 kg mixture of copper and aluminium, 30% is copper. How much aluminium powder should be added to the mixture so that the quantity of copper becomes 20% ?
Discuss
Answer & Solution
Answer: Option C
Solution:
According to the question,
Mixture of copper and aluminium = 2000 gms
30% copper = $$\frac{30}{100}$$ × 2000 = 600 gms
Aluminium in mixture = 2000 - 600 = 1400gm
Now 'x' weight of mixture have and 600 gm copper become 20% of its total weight.
i.e. x = $$\frac{{600}}{{20}} \times 100 $$   = 3000gm
Total amount of Aluminium in mixture = 3000 - 600 = 2400
Additional aluminium powder added = 2400 - 1400 = 1000gm
34
If 20% of (A + B) = 50% of B, then value of $$\frac{2A - B}{2A + B}$$   is :
Discuss
Answer & Solution
Answer: Option A
Solution:
$$\frac{20}{100}$$ (A + B) = $$\frac{50}{100}$$ (B)
2A + 2B = 5B
2A = 3B
A = $$\frac{3}{2}$$ put value of A in given equation
$$\frac{2A - B}{2A + B}$$
= $$\frac{3B - B}{3B + B}$$
= $$\frac{2B}{4B}$$
= $$\frac{1}{2}$$
35
Ticket for all but 100 seats in a 10000 seat stadium were sold. Of the ticket sold, 20% were sold at half price and the remaining tickets were sold at the full price of Rs. 20. The total revenue from the ticket sales, (in Rs.) was :
Discuss
Answer & Solution
Answer: Option B
Solution:
Total seats = 10000
Ticket sold = (10000 - 100) = 9900
According to the question,
Total revenue
= 9900 × $$\frac{20}{100}$$ × 10 + 9900 × $$\frac{80}{100}$$ × 20
= 9900 × 2 + 9900 × 16
= 9900 (2 + 16)
= Rs. 178200
36
The average of marks obtained by 100 candidates in a certain examination is 30. If the average marks of passed candidates is 35 and that of the failed candidates is 10, what is the number of candidates who passed the examinations ?
Discuss
Answer & Solution
Answer: Option C
Solution:
By mixture and allegation method.
Percentage mcq solution image
4 : 1 = 5 units
5 units = 100
1 unit = 20
Pass candidate :
= 4 units
= 4 × 20
= 80
37
If 90% of A = 30% of B and B = 2x% of A, then the value of x is :
Discuss
Answer & Solution
Answer: Option D
Solution:
90% of A = 30% of B
90A = 30B
⇒ B = 3A ..... (i)
B = $$\frac{2x}{100}$$ × A
3A = $$\frac{2x}{100}$$ × A
⇒ x = 150
38
18% of which number is equal to 12% of 75 ?
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the number = x
According to the question,
⇒ x × $$\frac{18}{100}$$ = $$\frac{12}{100}$$ × 75
⇒ 18x = 12 × 75
⇒ x = $$\frac{12 × 75}{18}$$
⇒ x = 50
Hence, required number = 50
39
Out of his total income, Mr. Kapur spends 20% on house rent and 70% of the rest on house hold expenses. If he saves Rs. 1800 what is his total income (in Rs.) ?
Discuss
Answer & Solution
Answer: Option D
Solution:
Let Mr.kapur income is 100x
House rent 20%, i.e. 20x
Remaining income 100x - 20x = 80x
Now 70% of his remaining income spend in house hold expenses
i.e. 70% of 80x = 56x
Remain saving is 80x - 56x = 24x
According to question
24x = 1800
x = $$\frac{{1800}}{{24}} = 75$$
Mr.kapur income = 100 × 75 = 7500
40
Two numbers are in the ratio 2 : 3. If 20% of the smaller number added to 20, is equal to the sum of 10% of the larger number and 25, the the smaller number is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the numbers are 2x and 3x respectively
According to the question,
2x × $$\frac{20}{100}$$ + 20 = 3x × $$\frac{10}{100}$$ + 25
$$\frac{2}{5}$$x + 20 = $$\frac{3}{10}$$ + 25
$$\frac{3}{10}$$x - $$\frac{2}{5}$$x = - 5
3x - 4x = - 50
x = 50
Hence, required smaller number
= 2x
= 2 × 50
= 100