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51
Out of two numbers, 40% of the greater number is equal to 60% of the smaller. If the sum of the numbers is 150, then the greater number is :
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the greater and smaller number is a and b respectively
According to the question,

Case (i)
a × $$\frac{40}{100}$$ = b × $$\frac{60}{100}$$
2a = 3b
a = $$\frac{3}{2}$$b ..... (i)

Case (ii)
a + b = 150 ..... (ii)
From equation (i) and (ii)
$$\frac{3}{2}$$b + b = 150
5b = 300
b = 60
Value of b = 60 put in equation (i)
a = $$\frac{3}{2}$$ × 60 = 90
Hence, greater number = 90
52
If the total monthly income of 16 persons is Rs. 80800 and the income of one of them is 120% of the average income, them his income is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Average income
= Rs. $$\frac{80800}{16}$$
= Rs. 5050
Hence, required income
= Rs. 5050 × $$\frac{120}{100}$$
= Rs. 6060
53
If three-fifth of sixty percent of a number is 36, the number is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the number be x
According to the question,
x × $$\frac{60}{100}$$ × $$\frac{3}{5}$$ = 36
⇒ x = $$\frac{36 × 25}{9}$$
⇒ x = 100
54
A number is first decreased by 10% and then increased by 10%. The number so obtained is 50 less than the original number. The original number is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the original number = x
According to the question,
x × $$\frac{90}{110}$$ × $$\frac{110}{100}$$ = (x - 50)
x × $$\frac{99}{100}$$ = x - 50
99x = 100x - 5000
x = 5000
Hence original number = 5000
55
X has twice as much money as that of Y and Y has 50% more money than that of Z. If the average money of all of them is Rs. 110, then the money, which X has is :
Discuss
Answer & Solution
Answer: Option D
Solution:
50% = $$\frac{1}{2}$$
Let Z has 2 units of money
According to the question,
X   :   Y   :   Z
6   :   3   :   2
$$\frac{(6 + 3 + 2)}{3}$$   units = Rs. 110
⇒ 11 units = Rs. 330
    1 unit = Rs. 30
6 units = 30 × 6 = Rs. 180
Hence, X has Rs. 180
56
The sum of two numbers is 520. If the bigger number is decreased by 4% and the smaller number is increased by 12% then the numbers obtained are equal. The smaller number is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Let the bigger number is a and the smaller number is (520 - a)
According to the question,
a × $$\frac{(100 - 4)}{100}$$   = (520 - a) × $$\frac{(100 + 12)}{100}$$
$$\frac{96a}{100}$$ = (520 - a) $$\frac{112}{100}$$
96a = (520 - a) 112
13a = 3640
a = 280
Hence, bigger number = 280
Smaller number = (520 - 280) = 240
57
Tulsiram's salary is 20% more then that of Kashyap. If Tulsiram saves Rs. 720 which is 4% of his salary, then Kashyap's salary is :
Discuss
Answer & Solution
Answer: Option A
Solution:
Salary of Tulsiram
= Rs. $$\frac{720}{4}$$ × 100
= Rs. 18000
Salary of Kashyap
= 18000 × $$\frac{100}{120}$$
= Rs. 15000
58
The ratio of the number of boys to that of girls in a village is 3 : 2. If 30% of boys and 70% of girls appeared in an examination, the ratio of the number of students, appeared in the examination to that not appeared in the same examination is :
Discuss
Answer & Solution
Answer: Option D
Solution:
According to the question,
Let the total number of students = 100
Ratio of Boys and Girls =$$\frac{3}{2}$$
Total number of Boy = $$\frac{3}{5} \times 100 = 60$$
Total number of Girl = $$\frac{2}{5} \times 100 = 40$$
30% of boy appeared in exam = 30% of 60 = 18
70% of girl appeared in exam = 70% of 40 = 28
Total number of student appeared in exam = 18 + 28 = 46
Students not appeared in exam = 100 - 46 = 54
$$\therefore \frac{{{\text{Ratio of students appeared in exam}}}}{{{\text{Not appeared in exam}}}}$$
= $$\frac{46}{54}$$
= $$\frac{23}{27}$$
= 23 : 27
59
The value of a machine is Rs. 6250. It decreases by 10% during the first year, 20% during the second year and 30% during the third year, What will be the value of the machine after 3 years ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Current value of machine
$$\eqalign{ & = 6250 \times \frac{{90}}{{100}} \times \frac{{80}}{{100}} \times \frac{{70}}{{100}} \cr & = {\text{Rs}}{\text{. 3150}} \cr} $$
60
A person gave 20% of his income to his elder son, 30% of remaining to the younger son and 10% of the balance, he donate to a trust. He is left with Rs. 10080. His income was :
Discuss
Answer & Solution
Answer: Option D
Solution:
Let Person income is 100x
20% his income give to elder son, i.e. 20x
Remaining income 100x -20x = 80x
Now 30% of his remaining income given to his younger son
i.e. 30% of 80x = 24x
Remain saving is 80x - 24x = 56x
Now 10% of his remaining income he donated to a trust
i.e. 10% of 56x = 5.6x
Remain income = 56x - 5.6x = 50.4x
According to question
50.4x = 10080
x = $$\frac{{10080}}{{50.4}}$$ = 200
Person income = 100 x 200 = Rs. 20000