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Percentage - Aptitude MCQ Questions and Solutions with Explanations

Percentage MCQ Questions and answers with easy and logical explanations.Arithmetic Ability provides you all type of quantitative and competitive aptitude mcq questions on Percentage with easy and logical explanations. Percentage MCQ is important for exams like Banking exams,IBPS,SCC,CAT,XAT,MAT etc. Page-6 section-1

Each section contains 100 MCQs on Percentage .
51
The actual area of a rectangle is 60 Cm2, but while measuring its length a student decreases it by 20% and the breadth increases by 25%. The percentage error in area, calculated by the student is :
Discuss
Answer & Solution
Answer: Option D
Solution:
100 === 25% ↑===> 125 ===> 20% ↓===> 100
So there is no change in the area of rectangle

Alternatively :
Let area be 1
Area of rectangle,
= l × b
= 0.8 × 1.25
= 1
52
The cost of packaging of the mangoes is 40% the cost of fresh mangoes themselves. The cost of mangoes increased by 30% but the cost of packaging decreased by 50%, then the percentage change of the cost of packed mangoes, if the cost of packed mangoes is equal to the sum of the cost of fresh mangoes and cost of packaging :
Discuss
Answer & Solution
Answer: Option B
Solution:
Cost of fresh mangoes + Cost of packaging = Total cost
Let initial Cost of fresh, mangoes = 100
Then, packaging cost = 40
Thus, Initial total cost = 100 + 40 = 140
After increasing in cost of fresh mangoes 30%,
Cost of fresh mangoes = 130
And cost of packing go down by 50 % so,
Cost of packing = 20
Now Total cost = 130 + 20 = 150
Increased cost = 150 - 140 = 10
% increased = $$ = \frac{{10 \times 100}}{{140}} = 7.14\% $$
53
220% of a number X is 44. What is 44% of X.
Discuss
Answer & Solution
Answer: Option A
Solution:
Given,
220% of X = 44
Or, X = 20
Thus,
44% of 20
$$ = \frac{{44 \times 20}}{{100}} = 8.8$$
54
The shopkeeper increased the price of a product by 25% so that customer finds difficult to purchase the required amount. But Somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product ?
Discuss
Answer & Solution
Answer: Option C
Solution:
Let initially the quantity and rate be 100 each
Quantity × rate = Expenditure
100 × 100 = 10000
Now, Increase in price is 25% and new quantity is 70% of original
Quantity × rate = Expenditure
70 × 125 = 8750
Decreased expenditure,
= 10000 - 8750 = 1250
% decrease $$ = \frac{{1250 \times 100}}{{10000}} = 12.5\% $$
55
A customer asks for the production of x number of goods. The company produces y number of goods daily. Out of which z% are units for sale. The order will be completed in :
Discuss
Answer & Solution
Answer: Option C
Solution:
$$\eqalign{ & {\text{Daily}}\,{\text{supply}}, \cr & = \left( {100 - z} \right)\% \,{\text{of}}\,y \cr & = \frac{{ {\left( {100 - z} \right)y} }}{{100}} \cr & {\text{Thus,}}\,{\text{required}}\,{\text{number}}\,{\text{of}}\,{\text{days}} \cr & = {\frac{{ {100x} }}{{\left( {100 - z} \right)y}}} \cr} $$
56
In the Science City, Kolkata the rate of the ticket is increased by 50% to increased the revenue but simultaneously 20% of the visitor decreased. What is percentage change in the revenue. if it is known that the Science city collects one revenue only from the visitors and it has no other financial supports:
Discuss
Answer & Solution
Answer: Option A
Solution:
Let the initial revenue be 100
100 === 50% ↑ (Ticket up) ===> 150 === 20% ↓ (Visitors down) ===> 120
There is 20% increase in the revenue
57
600 students took the test on Physics and chemistry. 35% students failed in Physics and 45% students failed in chemistry and 40% of those who passed in chemistry also passed in Physics, then how many students failed in both :
Discuss
Answer & Solution
Answer: Option D
Solution:
Result PhysicsChemistry
Failed35%45%
Passed65%55%


Now, 55% of 600 passed in Chemistry = $$\frac{{55 \times 600}}{{100}}$$   = 330
From question, 40% of those who passed in Chemistry(330 Students) also passed in physics
= $$\frac{{40 \times 330}}{{100}}$$
= 132,
so, 132 students passed in both
Therefore % who passed in both = $$\frac{{132 \times 100}}{{600}} = 22\% $$
Passed in both subject = 22% of total students
% of students who passed in either Physics or Chemistry or both,
= (65 + 55) - 22
= 98%
Thus, percentage of students who failed in both subjects = 2%
Number of students who failed = 2% of 600 = 12
58
An alloy contains the copper and aluminum in the ratio of 7 : 4 While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is :
Discuss
Answer & Solution
Answer: Option B
Solution:
Copper : Aluminum = 7 : 4
Let Copper and Aluminum in the weapon be 7x and 4x respectively
Given,
Aluminum in weapon = 12 kg
So,
→ 4x = 12
→ x = 3
Copper = 7x = 7 × 3 = 21 Kg.
Total alloy in the weapon = 12 + 21 = 33 kg
But 12% alloy get destroyed in making the weapon, i.e. 88% alloy is used in the weapon, so,
→ 88 % alloy = 33 kg
→ 100 % alloy = 37.5 kg
59
80% of a smaller number is 4 less than 40% of a larger number. The larger number is 85 greater than the smaller one. The sum of these two number is
Discuss
Answer & Solution
Answer: Option C
Solution:
Let the smaller number be x and larger number be y
According to the question,
80% of x + 4 = 40% of y
4y - 8x = 40
y - 2x = 10 --------- (1)
y - x = 85 ----------- (2)
By using (1) and (2), we get
x = 75
y = 160
x + y = 235
60
A number x is mistakenly divided by 10 instead of being multiplied by 10. what is the percentage error in the result?
Discuss
Answer & Solution
Answer: Option A
Solution:
Actual result = 10x
By mistake it has been divided by 10 = $$\frac{x}{{10}}$$
%Change = $$ {\frac{{10x - \left( {\frac{{10}}{x}} \right)}}{{10x}}} $$   × 100 = 99 = -99%
Since, actual value is greater than the wrong value.

Alternatively,
Let, x = 10
Actual result = 10 × 10 = 100
Wrong result = $$\frac{{10}}{{10}}$$ = 1
Change = (1 - 100) = -99
% Change = - 99%